WebHCF of 42, 49 and 63 can be found by prime factorization method: 42 = 2 × 3 × 7 49 = 7 × 7 63 = 3 × 3 × 7 The common factor in all three numbers is 7. So, the HCF of 42, 49 and 63 is 7. Therefore, the planks can be of length 7m. Now, we need to find the number of planks of length 7m that can be obtained from each of the given pieces of timber. WebHCF and LCM. HCF calculator is a multiservice tool that finds the highest common factor and lowest common factor of the given numbers at the same time. It only needs one …
HCF of 36 and 63 How to Find HCF of 36, 63? - Cuemath
WebTo find the HCF of 36 and 63, we will find the prime factorization of the given numbers, i.e. 36 = 2 × 2 × 3 × 3; 63 = 3 × 3 × 7. ⇒ Since 3, 3 are common terms in the prime factorization of 36 and 63. Hence, HCF (36, 63) = 3 × 3 = 9 ☛ What are Prime Numbers? If the HCF of 63 and 36 is 9, Find its LCM. HCF (63, 36) × LCM (63, 36) = 63 × 36 WebSolution. The lengths of the three pieces of timber are 42 m, 49 m, and 63 m. The greatest possible length of each plank will be given by the HCF of 42, 49, and 63. Firstly, we will … crush restaurant chico california
Three pieces of timber 42 m , 49 m and 63 m long have to …
Web42 = 2 x 3 x 7 63 = 3 x 3 x 7 140 = 2 x 2 x 5 x 7 LCM = 2*2*3*3*5*7 = 1260 HCF = 7 More answers below Deepti Pratihast B.Sc. in Mathematics & C++ (programming language), University of Delhi (Graduated 2024) 3 y Related What is H.C.F. of 42, 63, 140 =? Given numbers are 42, 63 and 140 Factorization of 42, 63 and 140 common factor = 7 WebSolution: Given numbers are 30 and 42. For finding the HCF of given numbers by division method, you need to take a large number i.e., 42 as dividend and a small number ie., 30 as a divisor. Now, divide 42 by 30 … WebSolution. The lengths of three pieces of timber are 42 m, 49 m and 63 m, respectively. We have to divide the timber into equal length of planks. ∴ Greatest possible length of each … crush review